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What will be the output of the following code snippet?
int[][] matrix = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
int max = matrix[0][0];
for (int[] row : matrix) {
for (int num : row) {
if (num > max) {
max = num;
}
}
}
System.out.println(max);
int max = matrix[0][0];
for (int[] row : matrix) {
for (int num : row) {
if (num > max) {
max = num;
}
}
}
System.out.println(max);
- a)1
- b)9
- c)7
- d)8
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
What will be the output of the following code snippet?int[][] matrix =...
The code initializes a 2D integer array "matrix" with elements {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}. The variable "max" is initially set to the value at index (0, 0) of the matrix. The nested for loop iterates over each element of the matrix and updates the "max" value if a greater number is found. Finally, the maximum value is printed, which is 9.
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Community Answer
What will be the output of the following code snippet?int[][] matrix =...
Understanding the Code Snippet
The provided code snippet initializes a 2D array (matrix) and aims to find the maximum value within it. Let's break down the components of the code to understand how it works.
Matrix Initialization
- The matrix is defined as follows:
{{1, 2, 3},
{4, 5, 6},
{7, 8, 9}}
- This creates a 3x3 matrix with the numbers 1 to 9.
Finding the Maximum Value
- The variable `max` is initialized with the first element of the matrix, which is `1`.
- The outer loop iterates over each row, while the inner loop iterates over each number in the current row.
- The condition `if (num > max)` checks if the current number is greater than the current maximum value. If true, it updates `max`.
Iterating Through the Matrix
- The loops will check each number in the matrix sequentially:
- From the first row: 1, 2, 3 (updates max to 3)
- From the second row: 4, 5, 6 (updates max to 6)
- From the third row: 7, 8, 9 (updates max to 9)
Final Output
- After iterating through all elements, the maximum value found will be `9`.
- The last statement prints the value of `max`, resulting in the output being `9`.
Conclusion
- The correct answer is option 'B', as the maximum value in the matrix is indeed `9`.
- Understanding the flow of loops and comparisons is crucial in finding the maximum value in a matrix.
The provided code snippet initializes a 2D array (matrix) and aims to find the maximum value within it. Let's break down the components of the code to understand how it works.
Matrix Initialization
- The matrix is defined as follows:
{{1, 2, 3},
{4, 5, 6},
{7, 8, 9}}
- This creates a 3x3 matrix with the numbers 1 to 9.
Finding the Maximum Value
- The variable `max` is initialized with the first element of the matrix, which is `1`.
- The outer loop iterates over each row, while the inner loop iterates over each number in the current row.
- The condition `if (num > max)` checks if the current number is greater than the current maximum value. If true, it updates `max`.
Iterating Through the Matrix
- The loops will check each number in the matrix sequentially:
- From the first row: 1, 2, 3 (updates max to 3)
- From the second row: 4, 5, 6 (updates max to 6)
- From the third row: 7, 8, 9 (updates max to 9)
Final Output
- After iterating through all elements, the maximum value found will be `9`.
- The last statement prints the value of `max`, resulting in the output being `9`.
Conclusion
- The correct answer is option 'B', as the maximum value in the matrix is indeed `9`.
- Understanding the flow of loops and comparisons is crucial in finding the maximum value in a matrix.
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